From 08130dd3d806a515694a888e907c5ba157562a67 Mon Sep 17 00:00:00 2001 From: mountdisk Date: Fri, 16 Aug 2024 21:34:52 +0800 Subject: [PATCH] chore: remove repetitive words Signed-off-by: mountdisk --- src/algorithms/sets/permutations/README.md | 2 +- src/algorithms/string/z-algorithm/zAlgorithm.js | 2 +- 2 files changed, 2 insertions(+), 2 deletions(-) diff --git a/src/algorithms/sets/permutations/README.md b/src/algorithms/sets/permutations/README.md index 4b6a268a..f58c4290 100644 --- a/src/algorithms/sets/permutations/README.md +++ b/src/algorithms/sets/permutations/README.md @@ -27,7 +27,7 @@ n * (n-1) * (n -2) * ... * 1 = n! ## Permutations with repetitions When repetition is allowed we have permutations with repetitions. -For example the the lock below: it could be `333`. +For example the lock below: it could be `333`. ![Permutation Lock](https://www.mathsisfun.com/combinatorics/images/combination-lock.jpg) diff --git a/src/algorithms/string/z-algorithm/zAlgorithm.js b/src/algorithms/string/z-algorithm/zAlgorithm.js index 4b96a4fc..57942522 100644 --- a/src/algorithms/string/z-algorithm/zAlgorithm.js +++ b/src/algorithms/string/z-algorithm/zAlgorithm.js @@ -48,7 +48,7 @@ function buildZArray(zString) { } // Now we may calculate how many characters starting from current position - // are are the same as the prefix. We may calculate it by difference between + // are the same as the prefix. We may calculate it by difference between // right and left Z box boundaries. zArray[charIndex] = zBoxRightIndex - zBoxLeftIndex;