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Add permutations and combinations.
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* [Least Common Multiple (LCM)](https://github.com/trekhleb/javascript-algorithms/tree/master/src/algorithms/math/least-common-multiple)
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* [Fisher–Yates Shuffle](https://github.com/trekhleb/javascript-algorithms/tree/master/src/algorithms/math/fisher-yates) - random permutation of a finite sequence
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* **String**
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* [String Permutations](https://github.com/trekhleb/javascript-algorithms/tree/master/src/algorithms/string/permutations)
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* [String Permutations](https://github.com/trekhleb/javascript-algorithms/tree/master/src/algorithms/string/permutations) - with and without repetitions
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* Combination
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* Minimum Edit distance (Levenshtein Distance)
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* Hamming
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@ -1,22 +1,41 @@
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# String Permutations
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A permutation, also called an “arrangement number” or “order”, is a rearrangement of
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the elements of an ordered list `S` into a one-to-one correspondence with `S` itself.
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A string of length `n` has `n!` permutation.
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Below are the permutations of string `ABC`.
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`ABC ACB BAC BCA CBA CAB`
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# Permutations
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When the order doesn't matter, it is a **Combination**.
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When the order **does** matter it is a **Permutation**.
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**"The combination to the safe is 472"**. We do care about the order. `724` won't work, nor will `247`.
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It has to be exactly `4-7-2`.
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## Permutations without repetitions
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A permutation, also called an “arrangement number” or “order”, is a rearrangement of
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the elements of an ordered list `S` into a one-to-one correspondence with `S` itself.
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Below are the permutations of string `ABC`.
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`ABC ACB BAC BCA CBA CAB`
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Or for example the first three people in a running race: you can't be first and second.
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**Number of combinations**
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```
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n * (n-1) * (n -2) * ... * 1 = n!
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```
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## Permutations with repetitions
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When repetition is allowed we have permutations with repetitions.
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For example the the lock below: it could be `333`.
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![Permutation Lock](https://www.mathsisfun.com/combinatorics/images/combination-lock.jpg)
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Permutation with repetitions example
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**Number of combinations**
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![Permutation With Repetitions](https://upload.wikimedia.org/wikipedia/commons/6/69/Permutations-With-Repetition.gif)
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```
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n * n * n ... (r times) = n^r
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```
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## References
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@ -1,28 +1,28 @@
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import permutateString from '../permutateString';
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import permutateWithoutRepetitions from '../permutateWithoutRepetitions';
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describe('permutateString', () => {
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it('should permutate string', () => {
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const permutations0 = permutateString('');
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const permutations0 = permutateWithoutRepetitions('');
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expect(permutations0).toEqual([]);
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const permutations1 = permutateString('A');
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const permutations1 = permutateWithoutRepetitions('A');
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expect(permutations1).toEqual(['A']);
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const permutations2 = permutateString('AB');
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const permutations2 = permutateWithoutRepetitions('AB');
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expect(permutations2.length).toBe(2);
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expect(permutations2).toEqual([
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'BA',
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'AB',
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]);
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const permutations6 = permutateString('AA');
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const permutations6 = permutateWithoutRepetitions('AA');
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expect(permutations6.length).toBe(2);
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expect(permutations6).toEqual([
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'AA',
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'AA',
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]);
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const permutations3 = permutateString('ABC');
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const permutations3 = permutateWithoutRepetitions('ABC');
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expect(permutations3.length).toBe(2 * 3);
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expect(permutations3).toEqual([
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'CBA',
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@ -33,7 +33,7 @@ describe('permutateString', () => {
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'ABC',
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]);
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const permutations4 = permutateString('ABCD');
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const permutations4 = permutateWithoutRepetitions('ABCD');
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expect(permutations4.length).toBe(2 * 3 * 4);
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expect(permutations4).toEqual([
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'DCBA',
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@ -62,7 +62,7 @@ describe('permutateString', () => {
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'ABCD',
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]);
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const permutations5 = permutateString('ABCDEF');
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const permutations5 = permutateWithoutRepetitions('ABCDEF');
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expect(permutations5.length).toBe(2 * 3 * 4 * 5 * 6);
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});
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});
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@ -1,4 +1,4 @@
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export default function permutateString(str) {
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export default function permutateWithoutRepetitions(str) {
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if (str.length === 0) {
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return [];
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}
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@ -11,7 +11,7 @@ export default function permutateString(str) {
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// Get all permutations of string of length (n - 1).
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const previousString = str.substring(0, str.length - 1);
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const previousPermutations = permutateString(previousString);
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const previousPermutations = permutateWithoutRepetitions(previousString);
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// Insert last character into every possible position of every previous permutation.
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const lastCharacter = str.substring(str.length - 1);
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