Fix typos (#59)

* Fixed typo in the word 'independant'

* Fixed typo in the word 'subsequnce'

* Fixed typo in the word 'icecream'

* Fixed typo in the word 'subsequnce' in shortestCommonSubsequence

* Fixed typo in the word 'depected'

* Fixed typo in the word 'paramaters'

src/algorithms/graph/articulation-points/articulationPoints.js

@@ -9,7 +9,7 @@ class VisitMetadata {
     this.lowDiscoveryTime = lowDiscoveryTime;
     // We need this in order to check graph root node, whether it has two
     // disconnected children or not.
-    this.independantChildrenCount = 0;
+    this.independentChildrenCount = 0;
   }
 }
 
@@ -49,7 +49,7 @@ export default function articulationPoints(graph) {
 
       if (previousVertex) {
         // Update children counter for previous vertex.
-        visitedSet[previousVertex.getKey()].independantChildrenCount += 1;
+        visitedSet[previousVertex.getKey()].independentChildrenCount += 1;
       }
     },
     /**
@@ -85,7 +85,7 @@ export default function articulationPoints(graph) {
       // 2. If its visited time is <= low time of adjacent vertex.
       if (previousVertex === startVertex) {
         // Check that root vertex has at least two independent children.
-        if (visitedSet[previousVertex.getKey()].independantChildrenCount >= 2) {
+        if (visitedSet[previousVertex.getKey()].independentChildrenCount >= 2) {
           articulationPointsSet[previousVertex.getKey()] = previousVertex;
         }
       } else {

src/algorithms/sets/longest-common-subsequence/__test__/longestCommonSubsequence.test.js

@@ -1,29 +1,29 @@
-import longestCommonSubsequnce from '../longestCommonSubsequnce';
+import longestCommonSubsequence from '../longestCommonSubsequence';
 
-describe('longestCommonSubsequnce', () => {
+describe('longestCommonSubsequence', () => {
   it('should find longest common subsequence for two strings', () => {
-    expect(longestCommonSubsequnce([''], [''])).toEqual(['']);
+    expect(longestCommonSubsequence([''], [''])).toEqual(['']);
 
-    expect(longestCommonSubsequnce([''], ['A', 'B', 'C'])).toEqual(['']);
+    expect(longestCommonSubsequence([''], ['A', 'B', 'C'])).toEqual(['']);
 
-    expect(longestCommonSubsequnce(['A', 'B', 'C'], [''])).toEqual(['']);
+    expect(longestCommonSubsequence(['A', 'B', 'C'], [''])).toEqual(['']);
 
-    expect(longestCommonSubsequnce(
+    expect(longestCommonSubsequence(
       ['A', 'B', 'C'],
       ['D', 'E', 'F', 'G'],
     )).toEqual(['']);
 
-    expect(longestCommonSubsequnce(
+    expect(longestCommonSubsequence(
       ['A', 'B', 'C', 'D', 'G', 'H'],
       ['A', 'E', 'D', 'F', 'H', 'R'],
     )).toEqual(['A', 'D', 'H']);
 
-    expect(longestCommonSubsequnce(
+    expect(longestCommonSubsequence(
       ['A', 'G', 'G', 'T', 'A', 'B'],
       ['G', 'X', 'T', 'X', 'A', 'Y', 'B'],
     )).toEqual(['G', 'T', 'A', 'B']);
 
-    expect(longestCommonSubsequnce(
+    expect(longestCommonSubsequence(
       ['A', 'B', 'C', 'D', 'A', 'F'],
       ['A', 'C', 'B', 'C', 'F'],
     )).toEqual(['A', 'B', 'C', 'F']);

src/algorithms/sets/longest-common-subsequence/longestCommonSubsequence.js

@@ -3,7 +3,7 @@
  * @param {string[]} set2
  * @return {string[]}
  */
-export default function longestCommonSubsequnce(set1, set2) {
+export default function longestCommonSubsequence(set1, set2) {
   // Init LCS matrix.
   const lcsMatrix = Array(set2.length + 1).fill(null).map(() => Array(set1.length + 1).fill(null));
 

src/algorithms/sets/shortest-common-supersequence/shortestCommonSupersequence.js

@@ -1,4 +1,4 @@
-import longestCommonSubsequnce from '../longest-common-subsequnce/longestCommonSubsequnce';
+import longestCommonSubsequence from '../longest-common-subsequence/longestCommonSubsequence';
 
 /**
  * @param {string[]} set1
@@ -8,9 +8,9 @@ import longestCommonSubsequnce from '../longest-common-subsequnce/longestCommonS
 
 export default function shortestCommonSupersequence(set1, set2) {
   // Let's first find the longest common subsequence of two sets.
-  const lcs = longestCommonSubsequnce(set1, set2);
+  const lcs = longestCommonSubsequence(set1, set2);
 
-  // If LCS is empty then the shortest common supersequnce would be just
+  // If LCS is empty then the shortest common supersequence would be just
   // concatenation of two sequences.
   if (lcs.length === 1 && lcs[0] === '') {
     return set1.concat(set2);

src/algorithms/sorting/counting-sort/README.md

@@ -32,7 +32,7 @@ element is very small.
 
 In first step we calculate the count of all the elements of the 
 input array `A`. Then Store the result in the count array `C`.
-The way we count is depected below.
+The way we count is depicted below.
 
 ![Counting Sort](https://3.bp.blogspot.com/-jJchly1BkTc/WLGqCFDdvCI/AAAAAAAAAHA/luljAlz2ptMndIZNH0KLTTuQMNsfzDeFQCLcB/s1600/CSortUpdatedStepI.gif)
 

src/algorithms/sorting/quick-sort/QuickSortInPlace.js

@@ -54,7 +54,7 @@ export default class QuickSortInPlace extends Sort {
     /*
      * While we can use a default parameter to set `low` to 0, we would
      * still have to set `high`'s default within the function as we
-     * don't have access to `array.length - 1` when declaring paramaters
+     * don't have access to `array.length - 1` when declaring parameters
      */
     const lowIndex = inputLowIndex === undefined ? 0 : inputLowIndex;
     const highIndex = inputHighIndex === undefined ? array.length - 1 : inputHighIndex;