Fix typos (#59)

* Fixed typo in the word 'independant'

* Fixed typo in the word 'subsequnce'

* Fixed typo in the word 'icecream'

* Fixed typo in the word 'subsequnce' in shortestCommonSubsequence

* Fixed typo in the word 'depected'

* Fixed typo in the word 'paramaters'
This commit is contained in:
Felix Rilling 2018-06-12 16:46:40 +02:00 committed by Oleksii Trekhleb
parent 19aa6fa4fc
commit 5734e0a43e
8 changed files with 19 additions and 19 deletions

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@ -9,7 +9,7 @@ class VisitMetadata {
this.lowDiscoveryTime = lowDiscoveryTime; this.lowDiscoveryTime = lowDiscoveryTime;
// We need this in order to check graph root node, whether it has two // We need this in order to check graph root node, whether it has two
// disconnected children or not. // disconnected children or not.
this.independantChildrenCount = 0; this.independentChildrenCount = 0;
} }
} }
@ -49,7 +49,7 @@ export default function articulationPoints(graph) {
if (previousVertex) { if (previousVertex) {
// Update children counter for previous vertex. // Update children counter for previous vertex.
visitedSet[previousVertex.getKey()].independantChildrenCount += 1; visitedSet[previousVertex.getKey()].independentChildrenCount += 1;
} }
}, },
/** /**
@ -85,7 +85,7 @@ export default function articulationPoints(graph) {
// 2. If its visited time is <= low time of adjacent vertex. // 2. If its visited time is <= low time of adjacent vertex.
if (previousVertex === startVertex) { if (previousVertex === startVertex) {
// Check that root vertex has at least two independent children. // Check that root vertex has at least two independent children.
if (visitedSet[previousVertex.getKey()].independantChildrenCount >= 2) { if (visitedSet[previousVertex.getKey()].independentChildrenCount >= 2) {
articulationPointsSet[previousVertex.getKey()] = previousVertex; articulationPointsSet[previousVertex.getKey()] = previousVertex;
} }
} else { } else {

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@ -30,7 +30,7 @@ It is often called "n choose r" (such as "16 choose 3"). And is also known as th
Repetition is Allowed: such as coins in your pocket `(5,5,5,10,10)` Repetition is Allowed: such as coins in your pocket `(5,5,5,10,10)`
Or let us say there are five flavours of icecream: Or let us say there are five flavours of ice cream:
`banana`, `chocolate`, `lemon`, `strawberry` and `vanilla`. `banana`, `chocolate`, `lemon`, `strawberry` and `vanilla`.
We can have three scoops. How many variations will there be? We can have three scoops. How many variations will there be?

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@ -1,29 +1,29 @@
import longestCommonSubsequnce from '../longestCommonSubsequnce'; import longestCommonSubsequence from '../longestCommonSubsequence';
describe('longestCommonSubsequnce', () => { describe('longestCommonSubsequence', () => {
it('should find longest common subsequence for two strings', () => { it('should find longest common subsequence for two strings', () => {
expect(longestCommonSubsequnce([''], [''])).toEqual(['']); expect(longestCommonSubsequence([''], [''])).toEqual(['']);
expect(longestCommonSubsequnce([''], ['A', 'B', 'C'])).toEqual(['']); expect(longestCommonSubsequence([''], ['A', 'B', 'C'])).toEqual(['']);
expect(longestCommonSubsequnce(['A', 'B', 'C'], [''])).toEqual(['']); expect(longestCommonSubsequence(['A', 'B', 'C'], [''])).toEqual(['']);
expect(longestCommonSubsequnce( expect(longestCommonSubsequence(
['A', 'B', 'C'], ['A', 'B', 'C'],
['D', 'E', 'F', 'G'], ['D', 'E', 'F', 'G'],
)).toEqual(['']); )).toEqual(['']);
expect(longestCommonSubsequnce( expect(longestCommonSubsequence(
['A', 'B', 'C', 'D', 'G', 'H'], ['A', 'B', 'C', 'D', 'G', 'H'],
['A', 'E', 'D', 'F', 'H', 'R'], ['A', 'E', 'D', 'F', 'H', 'R'],
)).toEqual(['A', 'D', 'H']); )).toEqual(['A', 'D', 'H']);
expect(longestCommonSubsequnce( expect(longestCommonSubsequence(
['A', 'G', 'G', 'T', 'A', 'B'], ['A', 'G', 'G', 'T', 'A', 'B'],
['G', 'X', 'T', 'X', 'A', 'Y', 'B'], ['G', 'X', 'T', 'X', 'A', 'Y', 'B'],
)).toEqual(['G', 'T', 'A', 'B']); )).toEqual(['G', 'T', 'A', 'B']);
expect(longestCommonSubsequnce( expect(longestCommonSubsequence(
['A', 'B', 'C', 'D', 'A', 'F'], ['A', 'B', 'C', 'D', 'A', 'F'],
['A', 'C', 'B', 'C', 'F'], ['A', 'C', 'B', 'C', 'F'],
)).toEqual(['A', 'B', 'C', 'F']); )).toEqual(['A', 'B', 'C', 'F']);

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@ -3,7 +3,7 @@
* @param {string[]} set2 * @param {string[]} set2
* @return {string[]} * @return {string[]}
*/ */
export default function longestCommonSubsequnce(set1, set2) { export default function longestCommonSubsequence(set1, set2) {
// Init LCS matrix. // Init LCS matrix.
const lcsMatrix = Array(set2.length + 1).fill(null).map(() => Array(set1.length + 1).fill(null)); const lcsMatrix = Array(set2.length + 1).fill(null).map(() => Array(set1.length + 1).fill(null));

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@ -1,4 +1,4 @@
import longestCommonSubsequnce from '../longest-common-subsequnce/longestCommonSubsequnce'; import longestCommonSubsequence from '../longest-common-subsequence/longestCommonSubsequence';
/** /**
* @param {string[]} set1 * @param {string[]} set1
@ -8,9 +8,9 @@ import longestCommonSubsequnce from '../longest-common-subsequnce/longestCommonS
export default function shortestCommonSupersequence(set1, set2) { export default function shortestCommonSupersequence(set1, set2) {
// Let's first find the longest common subsequence of two sets. // Let's first find the longest common subsequence of two sets.
const lcs = longestCommonSubsequnce(set1, set2); const lcs = longestCommonSubsequence(set1, set2);
// If LCS is empty then the shortest common supersequnce would be just // If LCS is empty then the shortest common supersequence would be just
// concatenation of two sequences. // concatenation of two sequences.
if (lcs.length === 1 && lcs[0] === '') { if (lcs.length === 1 && lcs[0] === '') {
return set1.concat(set2); return set1.concat(set2);

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@ -32,7 +32,7 @@ element is very small.
In first step we calculate the count of all the elements of the In first step we calculate the count of all the elements of the
input array `A`. Then Store the result in the count array `C`. input array `A`. Then Store the result in the count array `C`.
The way we count is depected below. The way we count is depicted below.
![Counting Sort](https://3.bp.blogspot.com/-jJchly1BkTc/WLGqCFDdvCI/AAAAAAAAAHA/luljAlz2ptMndIZNH0KLTTuQMNsfzDeFQCLcB/s1600/CSortUpdatedStepI.gif) ![Counting Sort](https://3.bp.blogspot.com/-jJchly1BkTc/WLGqCFDdvCI/AAAAAAAAAHA/luljAlz2ptMndIZNH0KLTTuQMNsfzDeFQCLcB/s1600/CSortUpdatedStepI.gif)

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@ -54,7 +54,7 @@ export default class QuickSortInPlace extends Sort {
/* /*
* While we can use a default parameter to set `low` to 0, we would * While we can use a default parameter to set `low` to 0, we would
* still have to set `high`'s default within the function as we * still have to set `high`'s default within the function as we
* don't have access to `array.length - 1` when declaring paramaters * don't have access to `array.length - 1` when declaring parameters
*/ */
const lowIndex = inputLowIndex === undefined ? 0 : inputLowIndex; const lowIndex = inputLowIndex === undefined ? 0 : inputLowIndex;
const highIndex = inputHighIndex === undefined ? array.length - 1 : inputHighIndex; const highIndex = inputHighIndex === undefined ? array.length - 1 : inputHighIndex;