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Add Rain Terraces problem.
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@ -128,6 +128,7 @@ a set of rules that precisely define a sequence of operations.
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* `B` [Square Matrix Rotation](src/algorithms/uncategorized/square-matrix-rotation) - in-place algorithm
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* `B` [Jump Game](src/algorithms/uncategorized/jump-game) - backtracking, dynamic programming (top-down + bottom-up) and greedy examples
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* `B` [Unique Paths](src/algorithms/uncategorized/unique-paths) - backtracking, dynamic programming and Pascal's Triangle based examples
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* `B` [Rain Terraces](src/algorithms/uncategorized/rain-terraces) - trapping rain water problem
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* `A` [N-Queens Problem](src/algorithms/uncategorized/n-queens)
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* `A` [Knight's Tour](src/algorithms/uncategorized/knight-tour)
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@ -2,11 +2,20 @@ import rainTerraces from '../rainTerraces';
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describe('rainTerraces', () => {
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it('should find the amount of water collected after raining', () => {
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expect(rainTerraces([1])).toBe(0);
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expect(rainTerraces([1, 0])).toBe(0);
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expect(rainTerraces([0, 1])).toBe(0);
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expect(rainTerraces([0, 1, 0])).toBe(0);
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expect(rainTerraces([0, 1, 0, 0])).toBe(0);
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expect(rainTerraces([0, 1, 0, 0, 1, 0])).toBe(2);
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expect(rainTerraces([0, 2, 0, 0, 1, 0])).toBe(2);
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expect(rainTerraces([2, 0, 2])).toBe(2);
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expect(rainTerraces([2, 0, 5])).toBe(2);
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expect(rainTerraces([3, 0, 0, 2, 0, 4])).toBe(10);
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expect(rainTerraces([0, 1, 0, 2, 1, 0, 1, 3, 2, 1, 2, 1])).toBe(6);
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expect(rainTerraces([1, 1, 1, 1, 1])).toBe(0);
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expect(rainTerraces([1, 2, 3, 4, 5])).toBe(0);
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expect(rainTerraces([4, 1, 3, 1, 2, 1, 2, 1])).toBe(4);
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expect(rainTerraces([0, 2, 4, 3, 4, 2, 4, 0, 8, 7, 0])).toBe(7);
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});
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});
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@ -2,76 +2,84 @@
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* @param {number[]} terraces
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* @return {number}
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*/
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export default function rainTerraces(terraces) {
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/*
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* STEPS
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*
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* 1. Find the highest terraces on the left and right side of the elevation map:
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* e.g. [0, 2, 4, 3, 1, 2, 4, 0, 8, 7, 0] => (leftMax = 4, rightMax = 8)
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* e.g. for [0, 2, 4, 3, 4, 2, 4, 0, 8, 7, 0] we would have leftMax = 4 and rightMax = 8.
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* This is because water will "trail off" the sides of the terraces.
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*
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* 2. At this point, we are essentially dealing with a new map: [4, 3, 4, 2, 4, 0, 8].
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* From here, we loop through the map from the left to the right (if leftMax > rightMax,
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* otherwise we move from right to left), adding water as we go unless we reach a value
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* that is greater than or equal to leftMax || rightMax.
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* From here, we loop through the map from the left to the right if leftMax < rightMax
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* (otherwise we move from right to left), adding water as we go unless we reach a value
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* that is greater than or equal to leftMax or rightMax.
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* e.g. [4, 3, 4, 2, 4, 0, 8]
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* ^
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* water += leftMax - 3 => water = 1
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* water = water + (leftMax - 3) = 1
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*
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* or if the terrace array was reversed:
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* e.g. [8, 0, 4, 2, 4, 3, 4]
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* ^
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* water += rightMax - 3 => water = 1
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* water = water + (rightMax - 3) = 1
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*
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* 3. Again, we've essentially shortened the map: [4, 2, 4, 0, 8].
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* Now we repeat the above steps on the new array.
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* e.g.
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*
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* Next Iteration:
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* [4, 2, 4, 0, 8]
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* ^
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* water += leftMax - 2 => water = 3
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* water = water + (leftMax - 2) = 3
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*
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* Next Iteration:
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* [4, 0, 8]
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* ^
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* water += leftMax - 0 => water = 7
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* water = water + (leftMax - 0) = 7
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*
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* return water(7)
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* 4. Return result: 7
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*/
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export default function rainTerraces(terraces) {
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let start = 0;
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let end = terraces.length - 1;
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let water = 0;
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let leftMax = 0;
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let rightMax = 0;
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let leftIndex = 0;
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let rightIndex = terraces.length - 1;
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while (start < end) {
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// Loop to find left max
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while (start < end && terraces[start] <= terraces[start + 1]) {
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start += 1;
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let leftMaxLevel = 0;
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let rightMaxLevel = 0;
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let waterAmount = 0;
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while (leftIndex < rightIndex) {
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// Loop to find the highest terrace from the left side.
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while (leftIndex < rightIndex && terraces[leftIndex] <= terraces[leftIndex + 1]) {
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leftIndex += 1;
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}
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leftMax = terraces[start];
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// Loop to find right max
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while (end > start && terraces[end] <= terraces[end - 1]) {
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end -= 1;
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leftMaxLevel = terraces[leftIndex];
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// Loop to find the highest terrace from the right side.
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while (rightIndex > leftIndex && terraces[rightIndex] <= terraces[rightIndex - 1]) {
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rightIndex -= 1;
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}
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rightMax = terraces[end];
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// Determine which direction we need to move in
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if (leftMax < rightMax) {
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// Move from left to right and collect water
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start += 1;
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while (start < end && terraces[start] <= leftMax) {
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water += leftMax - terraces[start];
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start += 1;
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rightMaxLevel = terraces[rightIndex];
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// Determine which direction we need to go.
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if (leftMaxLevel < rightMaxLevel) {
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// Move from left to right and collect water.
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leftIndex += 1;
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while (leftIndex < rightIndex && terraces[leftIndex] <= leftMaxLevel) {
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waterAmount += leftMaxLevel - terraces[leftIndex];
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leftIndex += 1;
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}
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} else {
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// Move from left to right and collect water
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end -= 1;
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while (end > start && terraces[end] <= rightMax) {
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water += rightMax - terraces[end];
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end -= 1;
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// Move from right to left and collect water.
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rightIndex -= 1;
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while (leftIndex < rightIndex && terraces[rightIndex] <= rightMaxLevel) {
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waterAmount += rightMaxLevel - terraces[rightIndex];
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rightIndex -= 1;
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}
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}
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}
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return water;
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return waterAmount;
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}
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