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Fix btPowerSet() comments.
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@ -6,16 +6,23 @@
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* @return {*[][]} - All subsets of original set.
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* @return {*[][]} - All subsets of original set.
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*/
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*/
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function btPowerSetRecursive(originalSet, allSubsets = [[]], currentSubSet = [], startAt = 0) {
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function btPowerSetRecursive(originalSet, allSubsets = [[]], currentSubSet = [], startAt = 0) {
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// In order to avoid duplication we need to start from next element every time we're forming a
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// Let's iterate over originalSet elements that may be added to the subset
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// subset. If we will start from zero then we'll have duplicates like {3, 3, 3}.
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// without having duplicates. The value of startAt prevents adding the duplicates.
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for (let position = startAt; position < originalSet.length; position += 1) {
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for (let position = startAt; position < originalSet.length; position += 1) {
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// Let's push current element to the subset.
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// Let's push current element to the subset
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currentSubSet.push(originalSet[position]);
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currentSubSet.push(originalSet[position]);
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// Current subset is already valid so let's memorize it.
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// Current subset is already valid so let's memorize it.
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// We do array destruction here to save the clone of the currentSubSet.
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// We need to save a clone since the original currentSubSet is going to be
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// mutated in further recursive calls.
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allSubsets.push([...currentSubSet]);
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allSubsets.push([...currentSubSet]);
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// Let's try to form all other subsets for the current subset.
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// Let's try to generate all other subsets for the current subset.
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// We're increasing the position by one to avoid duplicates in subset.
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btPowerSetRecursive(originalSet, allSubsets, currentSubSet, position + 1);
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btPowerSetRecursive(originalSet, allSubsets, currentSubSet, position + 1);
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// BACKTRACK. Exclude last element from the subset and try the next one.
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// BACKTRACK. Exclude last element from the subset and try the next valid one.
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currentSubSet.pop();
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currentSubSet.pop();
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}
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}
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